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K1 and K2 are equilibrium constants for reactions (i) and (ii) N2(g) + O2(g) ⇌ 2NO(g) ............(i) NO(g) ⇌ 1/2 N2(g) + 1/2 O2(g) ......(ii) Then:

1. K1 = (1 / K2)²
2. K1 = K2²
3. K1 = 1 / K2
4. K1 = (K2)⁰

Correct answer: K1 = (1 / K2)²

Solution

The equilibrium constant for reaction (ii) is the reciprocal of the square root of K1 because reaction (ii) is the reverse of reaction (i) with stoichiometric coefficients halved. Thus, K1 = (1 / K2)².

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