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The dissociation equilibrium of a gas AB2 can be represented as: 2AB2(g) ⇌ 2AB(g) + B2(g). The degree of dissociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure P is:

1. 2Kp/P
2. 2Kp/P^1/3
3. Kp/P^1/2
4. Kp/P

Correct answer: 2Kp/P

Solution

For the given equilibrium, the equilibrium constant Kp is expressed in terms of partial pressures. Since the degree of dissociation 'x' is small, the total pressure P can be approximated to simplify the expression. The correct relation is 2Kp/P.

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