Exams › NEET › Chemistry

Given that the equilibrium constant for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? SO3(g) ⇌ SO2(g) + 1/2 O2(g)

1. 1.8 × 10^-3
2. 3.6 × 10^-3
3. 6.0 × 10^-2
4. 1.3 × 10^-5

Correct answer: 1.8 × 10^-3

Solution

The equilibrium constant for the reverse reaction is the reciprocal of the forward reaction's constant. Additionally, since the coefficients are halved, the square root of the reciprocal is taken. Thus, K = 1/278^(1/2) = 1.8 × 10^-3.

Related NEET Chemistry questions

• A beaker contains a saturated solution of copper(l) chloride. Copper(l) chloride is slightly soluble salt with a solubility product of \( 1.2 \times 10^{-6} \) Which of the following salts when added to the solution would precipitate copper(l) chloride?
• The function of 'buffer solution' is:
• When \( C a(O H)_{2} \) attains solubility equilibrium, the:
• Predict if there will be any precipitate by mixing \( 50 \mathrm{mL} \) of \( 0.01 \mathrm{M} \) NaCl and 50 mL of \( 0.01 \mathrm{M} A g N O_{3} \) solution. The solubility product of \( A g C l \) is \( 1.5 \times \) \( 10^{-10} \)
• Calculate the ratio of \( H C O O^{-} \) and \( F^{-} \) in a mixture of \( 0.2 M \) HCOOH \( \left(K_{a}=\right. \) \( \left.2 \times 10^{-4}\right) \) and \( 0.1 M H F\left(K_{a}=6.6 \times\right. \) \( \left.10^{-4}\right) \)
• What is the [OH⁻] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)₂?

⚔️ Practice NEET Chemistry free + battle 1v1 →