The half-life of a substance in a certain enzyme catalysed reaction is 138s. The time required for the concentration of the substance to fall from 1.28 mg L⁻¹ to 0.04 mg L⁻¹ is:

Question

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552 s. The reaction follows first-order kinetics since the half-life is constant. Using the formula for first-order reactions, t = (2.303/k) log(C₀/C), and substituting k = 0.693/t₁/₂, we calculate the time required for the concentration to decrease from 1.28 mg L⁻¹ to 0.04 mg L⁻¹ as approximately 552 s.

The half-life of a substance in a certain enzyme catalysed reaction is 138s. The time required for the concentration of the substance to fall from 1.28 mg L⁻¹ to 0.04 mg L⁻¹ is:

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