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In the following sequence of reactions: CH3–Br →(KCN)→ A →(H3O+)→ B →(LiAlH4, ether)→ C, the end product (C) is:

1. Acetone
2. Methane
3. Acetaldehyde
4. Ethyl alcohol

Correct answer: Ethyl alcohol

Solution

In the given sequence, CH3–Br reacts with KCN to form CH3–CN (A). Hydrolysis of CH3–CN with H3O+ gives CH3–COOH (B). Reduction of CH3–COOH with LiAlH4 produces CH3–CH2OH (C), which is ethyl alcohol.

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