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Consider the following reaction: PhBr →(alc.KOH)→ X →(H2SO4, room temperature)→ Y →(H2O, heat)→ Z The product Z is:

1. CH3CH2–O–CH2–CH3
2. CH3–CH2–O–SO3H
3. CH3CH2OH
4. CH2=CH2

Correct answer: CH2=CH2

Solution

The reaction involves elimination of HBr from PhBr using alcoholic KOH to form ethene (CH2=CH2). Subsequent steps do not alter the ethene structure significantly, leading to Z as CH2=CH2.

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