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The equation k = Ae^(−Eₐ/RT) can be rearranged to give log k = log A − Eₐ/(2.303RT). Comparing this with y = mx + c, the slope of the plot of log k vs 1/T is:

1. Eₐ/2.303R
2. −Eₐ/2.303R
3. Eₐ/RT
4. −Eₐ/RT

Correct answer: −Eₐ/2.303R

Solution

The equation log k = log A − Eₐ/(2.303RT) is linear in form, where the slope corresponds to −Eₐ/(2.303R) when log k is plotted against 1/T.

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