The rate of the reaction 2N₂O₅ → 4NO₂ + O₂ can be written in three ways :
-d[N₂O₅]/dt = k [N₂O₅]
d[NO₂]/dt = k' [N₂O₅]
d[O₂]/dt = k'' [N₂O₅]
The relationship between k and k' and k'' are :

Question

Accepted Answer

k' = 2k ; k'' = k. The stoichiometric coefficients in the reaction dictate the relationship between the rate constants. For NO₂, the coefficient is 4, so k' = 2k. For O₂, the coefficient is 1, so k'' = k.

The rate of the reaction 2N₂O₅ → 4NO₂ + O₂ can be written in three ways : -d[N₂O₅]/dt = k [N₂O₅] d[NO₂]/dt = k' [N₂O₅] d[O₂]/dt = k'' [N₂O₅] The relationship between k and k' and k'' are :

Solution

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