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The compound CH3 − C ≡ CH − CH3 on reaction with NaIO4 in the presence of KMnO4 gives:

1. CH3CHO + CO2
2. CH3COCH3
3. CH3COCH3 + CH3COOH
4. CH3COCH3 + CH3CHO

Correct answer: CH3COCH3 + CH3CHO

Solution

The compound undergoes oxidative cleavage of the triple bond in the presence of NaIO4 and KMnO4, producing CH3COCH3 (acetone) and CH3CHO (acetaldehyde).

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