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What is the degree of dissociation (α) for a weak electrolyte given Ka = 1.00 × 10−5 and C = 0.100 mol?

1. α = √(Ka/C) = √(1 × 10−5/0.100) = 10−2 = 1%
2. Given Ka = 1.00 × 10−5, C = 0.100 mol
3. α = √(Ka/C) = 0.037
4. Ka = (0.037)2 × 0.10 = 1.37 × 10−4

Correct answer: α = √(Ka/C) = √(1 × 10−5/0.100) = 10−2 = 1%

Solution

The degree of dissociation (α) for a weak electrolyte is calculated using the formula α = √(Ka/C). Substituting the given values, α = √(1 × 10−5 / 0.100) = √(10−4) = 10−2 = 1%.

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