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What is the concentration of CH3COOH given Ka = 1.7 × 10−5 and [CH3COO−] = [H+] = 3.4 × 10−4 M?

1. [CH3COOH] = (3.4 × 10−4)(3.4 × 10−4)/1.7 × 10−5
2. [CH3COOH] = 6.8 × 10−3 M
3. Ka = [CH3COO−][H+]/[CH3COOH]
4. [CH3COOH] = 3.4 × 10−4 × 3.4 × 10−4

Correct answer: [CH3COOH] = (3.4 × 10−4)(3.4 × 10−4)/1.7 × 10−5

Solution

The dissociation constant Ka is given by the formula Ka = [CH3COO−][H+]/[CH3COOH]. Rearranging for [CH3COOH], we get [CH3COOH] = ([CH3COO−][H+])/Ka. Substituting the values, [CH3COOH] = (3.4 × 10−4)(3.4 × 10−4)/1.7 × 10−5.

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