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What is the pH of a solution with molarity (M) = 10M of HCl?

1. pH = log[H+] = log[10] = 1
2. Kw at 25°C = 1 × 10−14
3. Kw = [H+][OH−] = 10−14
4. pH = log[H+] = log[55 × 10−14]1/2

Correct answer: pH = log[H+] = log[10] = 1

Solution

HCl is a strong acid and dissociates completely in water. For a 10M HCl solution, [H+] = 10M, so pH = -log[H+] = -log(10) = 1.

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