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The following equilibrium constants are given: N2 + 3H2 ⇌ 2NH3; K1 N2 + O2 ⇌ 2NO; K2 H2 + 1/2 O2 ⇌ H2O; K3 The equilibrium constant for the oxidation of 2 moles NH3 by oxygen to give NO is:

1. K2 × K3 / K1
2. K2² × K3 / K1
3. K1 × K2 / K3
4. K2 × K3³ / K1

Correct answer: K2² × K3 / K1

Solution

The reaction for the oxidation of 2 moles of NH3 to NO can be derived by combining the given reactions. Using the equilibrium constant relationships, the correct expression is K2² × K3 / K1.

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