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The values of KP1 and KP2 for the reactions X ⇌ Y + Z ...(a) and A ⇌ 2B ...(b) are in the ratio of 9:1. If degree of dissociation of X and A be equal, then total pressure at equilibrium for (a) and (b) are in the ratio:

1. 3:1
2. 1:9
3. 36:1
4. 1:1

Correct answer: 3:1

Solution

The equilibrium constant KP is proportional to the total pressure raised to the power of the change in the number of moles (Δn). For reaction (a), Δn = 1, and for reaction (b), Δn = 1. Since the degree of dissociation is equal and KP1/KP2 = 9/1, the total pressure ratio is √9:√1 = 3:1.

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