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A 20 litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be: (Given that: SrCO3(s) ⇌ SrO(s) + CO2(g), Kp = 1.6 atm)
- 20 litre
- 4 litre
- 2 litre
- 5 litre
Correct answer: 4 litre
Solution
The equilibrium constant Kp = 1.6 atm determines the maximum pressure of CO2. Using the ideal gas law, the maximum volume is calculated when the pressure of CO2 equals Kp. At P = 1.6 atm, V = nRT/P = (0.4 × 20)/1.6 = 4 L.
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