Exams › NEET › Chemistry › Hydrogen
24 questions with worked solutions.
Q1. Which of the following can be used to prepare hydrogen gas in the laboratory?
Answer: Acid plus zinç
Zinc reacts with dilute acids to produce hydrogen gas, making it a common laboratory preparation method. The other options are used for different reactions or do not generate hydrogen under normal lab conditions.
Q2. Heavy water is obtained by?
Answer: Prolonged electrolysis of \( H_{2} O \)
Heavy water is deuterium oxide, so it is obtained by enriching water in deuterium. Prolonged electrolysis preferentially removes ordinary hydrogen, gradually increasing the concentration of heavy water.
Q3. The catalyst used in preparation of oxygen from hydrogen peroxide is:
Answer: manganese dioxide
Manganese dioxide catalyzes the decomposition of hydrogen peroxide into water and oxygen without being consumed. It is the standard catalyst used in laboratory preparation of oxygen from H2O2.
Q4. Wilkinson's catalyst \( \left[R h\left(P h_{3} P\right)_{3} C l\right] \) is used for:
Answer: hydrogenation of alkenes
Wilkinson's catalyst, Rh(PPh3)3Cl, is a classic homogeneous hydrogenation catalyst. It is especially used to hydrogenate alkenes to alkanes by adding hydrogen across carbon–carbon double bonds.
Q5. Which of the following option best describe the hydrogen economy?
Answer: Both (a) and (b)
The hydrogen economy refers to a system where hydrogen is produced, stored, transported, and used efficiently as an energy carrier. It also involves carrying and storing hydrogen in practical forms such as compressed gas or liquid hydrogen, so both (a) and (b) fit.
Q6. Which of the following is absorbed by H2SO4 in the given reaction?
Answer: H2O
H2SO4 is a strong dehydrating agent and readily absorbs water (H2O) from its surroundings or reactions.
Answer: Passing steam through a red hot coke bed
Water gas is produced by passing steam over red hot coke, which results in a mixture of carbon monoxide (CO) and hydrogen (H2).
Q8. Which one of the following molecular hydrides acts as a Lewis acid?
Answer: B2H6
B2H6 (diborane) acts as a Lewis acid because it has electron-deficient boron atoms that can accept electron pairs. The other options are not electron-deficient and do not exhibit Lewis acid behavior.
Q9. Which of the following statements about hydrogen is incorrect?
Answer: hydrogen has three isotopes of which tritium is the most common.
The incorrect statement is A because tritium is the least common isotope of hydrogen, not the most common. Protium is the most abundant isotope of hydrogen.
Answer: (b) (a) and (b)
Heavy water (D₂O) is used as a moderator in nuclear reactors due to its ability to slow down neutrons. It is also more associated than ordinary water because of stronger hydrogen bonding. However, it is not a more effective solvent than ordinary water.
Q11. The method used to remove temporary hardness of water is:
Answer: Clark’s method
Clark's method involves adding calcium hydroxide to remove temporary hardness caused by bicarbonates of calcium and magnesium.
Q12. Which of the following groups of ions makes the water hard?
Answer: (b) Magnesium and chloride
Hardness of water is caused by the presence of divalent cations like magnesium (Mg²⁺) and calcium (Ca²⁺). Among the options, magnesium and chloride contribute to water hardness.
Q13. The volume strength of 1.5 N H2O2 solution is
Answer: (c) 84L
Volume strength of H2O2 is calculated using the formula: Volume strength = Normality × 5.6. Substituting 1.5 N, we get 1.5 × 5.6 = 8.4 L, which matches option (c).
Q14. When H2O2 is oxidised, the product is
Answer: (b) O2
When H2O2 is oxidized, it loses electrons and forms molecular oxygen (O2) as the product. This is a well-known reaction of hydrogen peroxide in its role as a reducing agent.
Q15. Which of the following is the true structure of H2O2?
Answer: (b) O–O | | H H
The correct structure of H2O2 is a non-planar structure with an O–O single bond and two hydroxyl groups attached to the oxygen atoms, represented as H–O–O–H.
Q16. The O–O–H bond angle in H2O2 is
Answer: (d) 97°
The O–O–H bond angle in H2O2 is approximately 97° due to the repulsion between lone pairs on oxygen atoms and the bent structure of the molecule.
Q17. Match the following and identify the correct option.
Answer: (C) B2H6 (iii) Synthesis gas
The correct matches are: (A) - (iii) as CO and H2 form synthesis gas, (B) - (i) as temporary hardness is due to bicarbonates, (C) - (ii) as B2H6 is an electron-deficient hydride, and (D) - (iv) as H2O2 has a non-planar structure.
Q18. Pure nitrogen is prepared in the laboratory by heating a mixture of
Answer: NH4Cl + NaNO2
Pure nitrogen is prepared in the laboratory by heating a mixture of ammonium chloride (NH4Cl) and sodium nitrite (NaNO2), which react to produce nitrogen gas, water, and sodium chloride.
Q19. Of the following hydrides which one has the lowest boiling point?
Answer: PH3
PH3 has the lowest boiling point because it lacks strong hydrogen bonding, unlike NH3, and is lighter than SbH3 and AsH3, which have higher molecular weights.
Q20. HI can be prepared by all the following methods, except
Answer: (b) KI + H₂SO₄
HI cannot be prepared by reacting KI with H₂SO₄ because H₂SO₄ oxidizes HI to I₂, preventing its isolation. The other methods are valid for HI preparation.