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If there are 999 bases in an RNA that codes for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?

1. 1
2. 33
3. 333
4. 1

Correct answer: 33

Solution

A 999-base coding sequence makes 333 codons total. Deleting one base at position 901 shifts the reading frame starting at codon 301, so all codons from 301 through 333 are altered: 333 - 300 = 33.

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