Exams › JEE Main › Physics

Statement-1: In Young's double-slit experiment, the spacing between any two consecutive points that have intensity equal to half the maximum intensity is the same. Statement-2: In YDSE the intensity on the screen varies uniformly (linearly) with distance from the central maximum. Choose the correct option.

1. Statement-1 is true, statement-2 is true and statement-2 is the correct explanation for statement-1.
2. Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.
3. Statement-1 is true, statement-2 is false.
4. Statement-1 is false, statement-2 is true.

Correct answer: Statement-1 is true, statement-2 is false.

Solution

Statement 1 is true: the cos² intensity pattern is periodic, so the points where I = I_max/2 are equally spaced. Statement 2 is false: the intensity varies as cos² (periodic/sinusoidal), not uniformly/linearly with distance.

Related JEE Main Physics questions

• The pupil opening of a human eye is about 2 mm. If the average wavelength of visible light is taken as 5000 Å, the eye’s approximate angular resolving limit is
• For a single-slit diffraction pattern, the condition corresponding to the appearance of secondary maxima is
• In a Fresnel biprism setup, the two lens positions give slit separations of 16 cm and 9 cm. What is the true separation between the slits?
• In a Young’s double-slit setup, two monochromatic sources emit light of wavelengths 2500 Å and 3500 Å. Which pair of fringe orders from the two patterns will fall at the same position?
• In a Young’s double-slit setup, the intensity at a bright fringe maximum is I0. The slit separation is d = 5bb, where bb is the wavelength of the light used. If the screen is placed at a distance D = 10d, what intensity is observed at the point directly opposite one of the slits?
• What is the relationship between the polarizing angle and the critical angle?

⚔️ Practice JEE Main Physics free + battle 1v1 →