Exams › JEE Main › Physics

For a single-slit diffraction pattern, the condition corresponding to the appearance of secondary maxima is

1. a sin θ = nλ
2. a sin θ = (2n − 1)λ/2
3. a sin θ = (2n − 1)λ
4. a sin θ = nλ/2

Correct answer: a sin θ = (2n − 1)λ/2

Solution

The condition for secondary maxima in a single-slit diffraction pattern occurs when the path difference between light from the edges of the slit is an odd multiple of half wavelengths, which is mathematically represented as a sin θ = (2n − 1)λ/2.

Related JEE Main Physics questions

• The pupil opening of a human eye is about 2 mm. If the average wavelength of visible light is taken as 5000 Å, the eye’s approximate angular resolving limit is
• In a Fresnel biprism setup, the two lens positions give slit separations of 16 cm and 9 cm. What is the true separation between the slits?
• In a Young’s double-slit setup, two monochromatic sources emit light of wavelengths 2500 Å and 3500 Å. Which pair of fringe orders from the two patterns will fall at the same position?
• In a Young’s double-slit setup, the intensity at a bright fringe maximum is I0. The slit separation is d = 5bb, where bb is the wavelength of the light used. If the screen is placed at a distance D = 10d, what intensity is observed at the point directly opposite one of the slits?
• What is the relationship between the polarizing angle and the critical angle?
• In a single-slit diffraction setup, if the slit width is increased to twice its initial value, what happens to the central bright fringe of the diffraction pattern?

⚔️ Practice JEE Main Physics free + battle 1v1 →