Correct answer: The net force on the system of Q plus the conducting shell is zero
Inside the cavity the external field is fully screened by the shell, yet Q is off-centre so the induced charges produce a non-uniform field on Q; therefore the net force on Q alone is not necessarily zero, and option about E acting directly is subtle. However, treating Q and the shell as one isolated system in electrostatic equilibrium, the internal forces are equal and opposite and the external uniform field produces equal and opposite surface forces, so the net force on the combined system is zero.