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If a unit positive charge is taken from point A to point B along the same equipotential surface, then what can be said about the potential difference V_A - V_B?

1. V_A - V_B is positive
2. V_A - V_B is negative
3. V_A - V_B is zero
4. The charge remains at rest

Correct answer: V_A - V_B is zero

Solution

On an equipotential surface every point is at the same potential, so V_A - V_B = 0.

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