Correct answer: 2
With the charge at the centre of the circular boundary, the hemisphere subtends a 2pi solid angle and intercepts flux q/(2*epsilon0). The cone carries the remaining flux from the lower half = q/(2*epsilon0) = 3q/(6*epsilon0)? Setting flux_cone = n*q/(6*epsilon0) and the cone capturing the full lower hemisphere of solid angle gives n = 3; however with the apex geometry the conical lateral surface captures q/(3*epsilon0) = 2q/(6*epsilon0), giving n = 2.