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A constant electric field E is directed along the positive x-axis. If a charge of 0.5 C is displaced by 2 m along a line inclined at 60° to the x-axis, and the work done in this process is 10 J, what is the magnitude of the electric field?

1. 5 V m⁻¹
2. 2 V m⁻¹
3. √5 V m⁻¹
4. 20 V m⁻¹

Correct answer: 20 V m⁻¹

Solution

W = q*E*d*cos(theta): 10 = 0.5*E*2*cos60 = 0.5*E. So E = 20 V/m.

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