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ExamsJEE MainPhysics

Using Heisenberg's uncertainty principle, calculate the minimum uncertainty in the velocity of a cricket ball of mass 150 g, given that the uncertainty in its position is of the order of 1 Angstrom (1 * 10⁻¹⁰ m).

  1. 3.52 * 10⁻²⁴ m/s
  2. 3.52 * 10⁻²³ m/s
  3. 3.52 * 10⁻²² m/s
  4. 3.52 * 10⁻²¹ m/s

Correct answer: 3.52 * 10⁻²⁴ m/s

Solution

From the uncertainty principle, delta_v >= h / (4 * pi * m * deltaₓ). Substituting values gives delta_v = 6.626*10⁻³⁴ / (4 * 3.1416 * 0.150 * 10⁻¹⁰) = 3.52 * 10⁻²⁴ m/s.

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