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Which of the following sets of quantum numbers corresponds to the electron with the highest energy?
- n = 2, l = 1, m = 0, s = +1/2
- n = 3, l = 0, m = 0, s = +1/2
- n = 4, l = 0, m = 1, s = +1/2
- n = 4, l = 1, m = 1, s = +1/2
Correct answer: n = 4, l = 1, m = 1, s = +1/2
Solution
Option D has n+l = 5, the highest among all valid options, so it corresponds to the highest energy electron (a 4p electron).
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