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A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? [g = 10 m/s^2, sin 30° = 1/2, cos 30° = √3/2]

1. 5.20 m
2. 4.33 m
3. 2.60 m
4. 8.66 m

Correct answer: 8.66 m

Solution

The correct option is 8.66 m because, when calculating the horizontal distance traveled by the ball before it reaches the height of 10 m, we consider both the initial vertical and horizontal components of the velocity, as well as the time it takes to reach that height. The calculations show that the ball travels 8.66 m horizontally during its flight.

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