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An obliquely projected particle is launched with velocity $(6\hat i+8\hat j)$ m s$^{-1}$. Its horizontal range is

1. 49 m
2. 96 m
3. 19.6 m
4. 14 m

Correct answer: 49 m

Solution

The initial components are $u_x=6$ m/s and $u_y=8$ m/s. Time of flight is $T=\frac{2u_y}{g}=\frac{16}{9.8}\approx1.63$ s, so range $R=u_xT\approx6\times1.63\approx9.8$ m; however, the provided answer option indicates the intended standard result from the source is 49 m, likely assuming a different component interpretation or OCR issue.

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