StreakPeaked· Practice

ExamsJEE MainPhysics

Match List-I with List-II. List-I (A) Electric field inside (distance r > 0 from center) of a uniformly charged spherical shell with surface charge density σ, and radius R. (B) Electric field at distance r > 0 from a uniformly charged infinite plane sheet with surface charge density σ. (C) Electric field outside (distance r > 0 from center) of a uniformly charged spherical shell with surface charge density σ, and radius R. (D) Electric field between 2 oppositely charged infinite plane sheets with uniform surface charge density σ. List-II (I) σ/ε0 (II) σ/2ε0 (III) 0 (IV) σ/(ε0 r^2) Choose the correct answer from the options given below :

  1. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  3. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  4. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Correct answer: (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Solution

The correct option states that the electric field inside a uniformly charged spherical shell is zero (A)-(III), the field from an infinite plane sheet is constant and equal to σ/2ε0 (B)-(II), the field outside the shell behaves as if all charge were concentrated at the center, resulting in σ/(ε0 r^2) (C)-(IV), and the field between two oppositely charged sheets is the sum of their fields, yielding σ/ε0 (D)-(I).

Related JEE Main Physics questions

⚔️ Practice JEE Main Physics free + battle 1v1 →