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ExamsJEE MainPhysics

Match the thermodynamic processes taking place in a system with the correct conditions. In the table : ΔQ is the heat supplied, ΔW is the work done and ΔU is the change in internal energy of the system. Process (I) Adiabatic (II) Isothermal (III) Isochoric (IV) Isobaric Condition (A) ΔW = 0 (B) ΔQ = 0 (C) ΔU ≠ 0, ΔW ≠ 0, ΔQ ≠ 0 (D) ΔU = 0

  1. (I) – (B), (II) – (A), (III) – (D), (IV) – (C)
  2. (I) – (B), (II) – (A), (III) – (B), (IV) – (C)
  3. (I) – (A), (II) – (B), (III) – (D), (IV) – (D)
  4. (I) – (B), (II) – (D), (III) – (A), (IV) – (C)

Correct answer: (I) – (A), (II) – (B), (III) – (D), (IV) – (D)

Solution

The correct option matches each thermodynamic process with its defining characteristics: in an adiabatic process, no heat is exchanged (ΔQ = 0), in an isothermal process, the internal energy remains constant (ΔU = 0), while in isochoric and isobaric processes, the volume and pressure are held constant, respectively, allowing for changes in internal energy and work done.

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