Exams › JEE Main › Physics
A Carnot engine operates with a diatomic ideal gas as its working fluid. During the adiabatic expansion stage, the gas volume rises from V to 32V. What is the efficiency of the engine?
- 0.50
- 0.75
- 0.99
- 0.25
Correct answer: 0.75
Solution
For diatomic gas gamma=7/5. Adiabatic: T_cold/T_hot = (V/32V)^(gamma-1) = 32^(-2/5) = 1/4. Efficiency = 1 - 1/4 = 0.75.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →