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Two simple harmonic motions are represented by the equations y1 = 0.1 sin(100πt + π/3) y2 = 0.1 cos πt . The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
- π/3
- -π/6
- π/6
- -π/3
Correct answer: π/6
Solution
The phase difference in the velocities of the two particles can be determined by differentiating their position equations to find their velocities. The velocity of particle 1 has a phase shift of π/3, while the velocity of particle 2 has a phase shift of 0. The difference between these phase shifts results in a phase difference of π/6.
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