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ExamsJEE MainPhysics

A particle undergoing simple harmonic motion has kinetic energy K0. The maximum potential energy and the total energy are, respectively,

  1. K0/2 and K0
  2. K0 and 2K0
  3. K0 and K0
  4. 0 and 2K0

Correct answer: K0 and K0

Solution

Taking the given K0 as the (maximum) kinetic energy, the total energy equals K0, and the maximum potential energy also equals the total energy, so both are K0.

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