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A particle undergoing simple harmonic motion has kinetic energy K0. The maximum potential energy and the total energy are, respectively,
- K0/2 and K0
- K0 and 2K0
- K0 and K0
- 0 and 2K0
Correct answer: K0 and K0
Solution
Taking the given K0 as the (maximum) kinetic energy, the total energy equals K0, and the maximum potential energy also equals the total energy, so both are K0.
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