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A block of mass 1 kg is connected to a spring of force constant 600 N/m and is at rest on a frictionless horizontal table, with the other end of the spring fixed to a wall. Another block of mass 0.5 kg moves along the table toward the first block with speed 3 m/s. If the two blocks undergo a perfectly inelastic collision, determine the amplitude and the time period of the motion of the joined mass.
- 5 cm, π/10 s
- 5 cm, π/5 s
- 4 cm, 2π/5 s
- 4 cm, π/5 s
Correct answer: 5 cm, π/10 s
Solution
After collision v = (0.5*3)/1.5 = 1 m/s, combined mass 1.5 kg. omega = sqrt(600/1.5) = 20 rad/s. A = v/omega = 1/20 = 0.05 m = 5 cm; T = 2pi/20 = pi/10 s.
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