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A magnet hung at 45° with magnetic meridian makes an angle of 60° with the horizontal. The actual value of the angle of dip is

1. tan⁻¹(√(3/2))
2. tan⁻¹(√6)
3. tan⁻¹(√(2/3))
4. tan⁻¹(1/√2)

Correct answer: tan⁻¹(√(3/2))

Solution

For a vertical plane at angle alpha to the magnetic meridian, tan(apparent) = tan(true)/cos(alpha). So tan(true) = tan60 * cos45 = sqrt(3)*(1/sqrt2) = sqrt(3/2). True dip = tan^-1(sqrt(3/2)).

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