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A bar magnet having a magnetic moment of 2.0 × 10⁵ J T⁻¹, is placed along the direction of uniform magnetic field of magnitude B = 14 × 10⁻⁵ T. The work done in rotating the magnet slowly through 60° from the direction of field is:
- 14 J
- 8.4 J
- 4 J
- 1.4 J
Correct answer: 14 J
Solution
The work done in rotating a magnetic moment in a magnetic field is given by the formula W = -mB(cosθ - cosθ0). In this case, the initial angle θ0 is 0° and the final angle θ is 60°, leading to a calculation that results in 14 J.
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