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0.056 kg of Nitrogen is enclosed in a vessel at temperature of 127°C. The amount of heat required to double the speed of its molecules is __ k cal. (Take R = 2 cal mol⁻¹ K⁻¹)
- 12.00
- 12.00
- 12.00
- 12.00
Correct answer: 12.00
Solution
To double the speed of the nitrogen molecules, we need to increase the temperature by a factor of four, since the speed of gas molecules is proportional to the square root of temperature. The heat required can be calculated using the formula Q = nC_vΔT, where n is the number of moles, C_v is the molar heat capacity at constant volume, and ΔT is the change in temperature, leading to the conclusion that 12.00 kcal is needed.
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