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A parallel plate capacitor is formed by two plates each of area 30π cm² separated by 1 mm. A material of dielectric strength 3.6 × 10⁷ V m⁻¹ is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7 × 10⁻⁶ C, the value of dielectric constant of the material is: [Use 1 / 4πε0 = 9 × 10⁹ N m² C⁻²]

1. 1.66
2. 1.75
3. 2.25
4. 2.33

Correct answer: 2.33

Solution

The dielectric constant is calculated using the formula relating charge, area, separation, and dielectric strength. Given the maximum charge and the dielectric strength, we can derive the dielectric constant, which turns out to be 2.33, indicating the material's ability to increase capacitance compared to a vacuum.

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