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The material filled between the plates of a parallel plate capacitor has resistivity 200 Ωm. The value of capacitance of the capacitor is 2 pF. If a potential difference of 40 V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is: (given value of relative permittivity of material is 50)

1. 9.0 μA
2. 9.0 mA
3. 0.9 mA
4. 0.9 μA

Correct answer: 0.9 mA

Solution

The leakage current in a capacitor can be calculated using the formula I = V/R, where R is the resistance derived from the resistivity and dimensions of the dielectric material. Given the resistivity and the applied voltage, the calculated leakage current of 0.9 mA is consistent with the values provided.

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