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ExamsJEE MainPhysics

The magnetic susceptibility of a material of a rod is 499. Permeability of vacuum is 4π × 10⁻⁷ H/m. Absolute permeability of the material of the rod is:

  1. 4π × 10⁻⁴ H/m
  2. 2π × 10⁻⁴ H/m
  3. 3π × 10⁻⁴ H/m
  4. π × 10⁻⁴ H/m

Correct answer: 2π × 10⁻⁴ H/m

Solution

The absolute permeability of a material can be calculated using the formula: μ = μ₀ (1 + χ), where μ₀ is the permeability of vacuum and χ is the magnetic susceptibility. Given that the susceptibility is 499, the absolute permeability becomes 4π × 10⁻⁷ H/m × (1 + 499), which simplifies to 2π × 10⁻⁴ H/m.

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