Exams › JEE Main › Physics
The correct relation between the degrees of freedom f and the ratio of specific heat γ is:
- (1) f = 2/(γ − 1)
- (2) f = 2/(γ + 1)
- (3) f = (γ + 1)/2
- (4) f = 1/(γ + 1)
Correct answer: (1) f = 2/(γ − 1)
Solution
The correct relation f = 2/(γ − 1) arises from the kinetic theory of gases, where the degrees of freedom f are related to the specific heat ratio γ, reflecting how energy is distributed among the translational and internal modes of motion in a gas.
Related JEE Main Physics questions
- An ideal gas is enclosed in a thermally insulated sealed container. During an adiabatic expansion, the mean interval between successive molecular collisions varies with the volume V as V^q. What is the value of q in terms of γ = Cp/Cv?
- At 300 K, the root mean square speed of hydrogen molecules is 1930 m/s. What will be the r.m.s. speed of oxygen molecules at 1200 K?
- A gaseous mixture contains 2 moles of oxygen and 4 moles of argon at temperature T. If vibrational degrees of freedom are ignored, what is the total internal energy of the mixture?
- If all intermolecular attractions were removed, what volume would be occupied by the molecules present in 4.5 g of water at standard temperature and pressure?
- An ideal gas sample has volume V, pressure P, and absolute temperature T. If the mass of one molecule is m, which expression gives the density of the gas?
- A vessel at temperature T contains N molecules of gas A, each having mass m, and 2N molecules of gas B, each having mass 2m. If the mean square speed of molecules of gas B is V2 and that of gas A is V1, then the ratio V1/V2 equals
⚔️ Practice JEE Main Physics free + battle 1v1 →