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The electric field in a region is given by E = (2/5)E0 i + (3/5)E0 j with E0 = 4.0×10³ N/C. The flux of this field through a rectangular surface area 0.4 m² parallel to the Y – Z plane is ________ Nm²C⁻¹.

1. 320
2. 480
3. 640
4. 800

Correct answer: 640

Solution

Flux = Ex * A = (2/5)(4.0x10^3)(0.4) = 1600 x 0.4 = 640 Nm^2/C.

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