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A light wave is incident normally on a glass slab of refractive index 1.5. If 4% of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be:

1. 6 V/m
2. 10 V/m
3. 30 V/m
4. 24 V/m

Correct answer: 24 V/m

Solution

For normal incidence the transmitted electric-field amplitude is E_t = [2n1/(n1+n2)]*E_i = (2*1/(1+1.5))*30 = 0.8*30 = 24 V/m.

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