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If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be:
- V⁻² A² F²
- V⁻⁴ A⁻² F
- V⁻⁴ A² F
- V⁻² A² F⁻²
Correct answer: V⁻⁴ A² F
Solution
Young's modulus Y = [M L^-1 T^-2]. With V=[LT^-1], A=[LT^-2], F=[MLT^-2], solving the exponents gives Y = V^-4 A^2 F.
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