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ExamsJEE MainPhysics

A rod was found to have a measured length of 3.50 cm. Which measuring device was used for this reading?

  1. A metre rule
  2. A vernier caliper in which 10 vernier divisions coincide with 9 main-scale divisions, and the main scale has 10 divisions in 1 cm
  3. A screw gauge with 100 circular-scale divisions and a pitch of 1 mm
  4. A screw gauge with 50 circular-scale divisions and a pitch of 1 mm

Correct answer: A vernier caliper in which 10 vernier divisions coincide with 9 main-scale divisions, and the main scale has 10 divisions in 1 cm

Solution

A reading of 3.50 cm is given to 0.01 cm (0.1 mm). For the vernier where 10 VSD = 9 MSD and 1 MSD = 1 mm, least count = 1 MSD/10 = 0.1 mm = 0.01 cm, matching the reading. The screw gauges give 0.001 cm or 0.002 cm (three decimals), and a metre rule only 0.1 cm.

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