A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

Question

Accepted Answer

92 ± 2 s. Mean = (90+91+95+92)/4 = 92 s. Mean absolute deviation = (2+1+3+0)/4 = 1.5 s, which with least count 1 s is reported as 2 s. So the result is 92 +/- 2 s.

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

Solution

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