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A student measured the length of a rod and wrote its as 3.50 cm. Which instrument did he use to measure it ?
- A vernier calliper where the 10 divisions in vernier scale matches 9 division in main scale and main scale has 10 divisions in 1 cm
- A screw gauge having 100 divisions in the circular scale and pitch as 1 mm
- A screw gauge having 50 divisions in the circular scale and pitch as 1 mm
- A meter scale
Correct answer: A vernier calliper where the 10 divisions in vernier scale matches 9 division in main scale and main scale has 10 divisions in 1 cm
Solution
The correct option is a vernier caliper because it allows for precise measurements to the hundredth of a centimeter, which is necessary to accurately measure and record a length of 3.50 cm.
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