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Assume that an electric field E = 30x²î exists in space. Then the potential difference V_A - V_O, where V_O is the potential at the original and V_A the potential at x = 2 m is -

1. -120 J
2. -80 J
3. 80 J
4. 120 J

Correct answer: -80 J

Solution

The potential difference between two points in an electric field can be calculated using the formula V_A - V_O = - ∫_(O)^(A) E · dr. Here, integrating the electric field ext{E} = 30x² î from 0 to 2 meters results in a potential difference of -80 J, indicating that the potential at point A is lower than at point O.

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