Correct answer: 3 A
The correct option is right because the current required to demagnetize the small magnet can be calculated using the formula for the magnetic field inside a solenoid, which is proportional to the product of the current and the number of turns per unit length. Given the coercivity and the dimensions of the solenoid, a current of 3 A is necessary to achieve the required magnetic field to demagnetize the magnet.