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A parallel-plate capacitor is formed by arranging n plates at equal separations and connecting them alternately. If the capacitance between each neighboring pair of plates is C, what is the equivalent capacitance of the arrangement?

1. (n+1)C
2. (n-1)C
3. nC
4. C

Correct answer: (n-1)C

Solution

The equivalent capacitance of the arrangement is derived from the fact that each neighboring pair of plates contributes to the total capacitance, and with n plates, there are (n-1) such pairs. Therefore, the total capacitance is (n-1) times the capacitance of each pair, which is C.

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