A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 10¹²/sec. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver = 108 and Avogadro number = 6.02 × 10²³ gm mole⁻¹)

Question

Accepted Answer

7.1 N/m. Mass of one Ag atom = 108/(6.02e23) g = 1.79e-25 kg. Force constant k = m*omega^2 = m*(2*pi*f)^2 = 1.79e-25*(2*pi*1e12)^2 = 7.1 N/m.

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 10¹²/sec. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver = 108 and Avogadro number = 6.02 × 10²³ gm mole⁻¹)

Solution

Related JEE Main Physics questions